Acorn Hill, New York, United States
About
Acorn Hill is a summit located in Ulster county New York in the United States of America. It is at 42.0303694 latitude and -74.1731992 longitude. Acorn Hill is at an elevation of 398 ft (1306 m). The USGS map that contains this location is titled "Bearsville".
Location Details
| Type of Place: | Summit |
| Latitude: | 42.0303694 |
| Longitude: | -74.1731992 |
| Elevation: | 398 ft / 1306 m |
| County: | Ulster |
| USGS Map Name: | Bearsville |
